클래스 찾는 jsp 소스 (findClass.jsp)

Tech Note 정보
카테고리: [ Java ]
조회수: 23389

1. 목적

2. 코드

<%@ page import="java.util.*"%>
<%
    String reqName = null;
    java.net.URL classUrl = null;
 
    reqName = request.getParameter("reqName");
    if (reqName == null || reqName.trim().length() == 0) {
        reqName = "";
    }
%>
 
<html>
<body onLoad="document.form1.reqButton.focus();">
 
<br><hr align=center><br>
[Example]<br>
Java class path: <b><%=System.getProperties().getProperty("java.class.path")%></b><br><br>
Document Builder Factory - org.apache.xerces.jaxp.DocumentBuilderFactoryImpl<br>
SAX Parser Factory - org.apache.xerces.jaxp.SAXParserFactoryImpl<br>
Transformer Factory - org.apache.xalan.processor.TransformerFactoryImpl<br>
<br>
(ex) org.apache.xerces.jaxp.DocumentBuilderFactoryImpl<br>
 
<form action="findClass.jsp" name=form1>
<input type=text name= "reqName"value="<%= reqName %>">
<input type=submit name=reqButton value="FIND">
</form>
 
<%
    if (reqName.trim().length() != 0) {
%>
 
[Search Result]
<br>
<%
 reqName = reqName.replace('.', '/').trim();
 reqName = "/" + reqName + ".class";
        classUrl = this.getClass().getResource(reqName);
        if (classUrl == null) {
            out.println(reqName + " not found");
        } else {
            out.println("<b>" + reqName + "</b>: [" + classUrl.getFile() + "]"
);
        }
        out.println("<br>");
 
    }
%>